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In probability theory and statistics, a multivariate normal distribution, also sometimes called a multivariate Gaussian distribution, is a specific probability distribution, which can be thought of as a generalization to higher dimensions of the one-dimensional normal distribution (also called a Gaussian distribution).

General case


A random vector X = \dots, X_N follows a multivariate normal distribution if it satisfies the following equivalent conditions:

  • there is a vector \mu and a symmetric, positive semi-definite matrix \Sigma such that the characteristic function of X is

\phi_X(u;\mu,\Sigma) = \exp \left( i \mu^\top u - \frac{1}{2} u^\top \Sigma u \right)

The following is not quite equivalent to the conditions above, since it fails to allow for a singular matrix as the variance:

f_X(x_1, \dots, x_N) = \frac {1} {(2\pi)^{N/2} \left|\Sigma\right|^{1/2}} \exp \left( -\frac{1}{2} ( x - \mu)^\top \Sigma^{-1} (x - \mu) \right)

where \left| \Sigma \right| is the determinant of \Sigma. Note how the equation above reduces to that of the univariate normal distribution if \Sigma is a scalar (i.e., a real number).

The vector \mu in these conditions is the expected value of X and the matrix \Sigma = A A^T is the covariance matrix of the components X_i.

It is important to realize that the covariance matrix must be allowed to be singular. That case arises frequently in statistics; for example, in the distribution of the vector of residuals in ordinary linear regression problems. Note also that the X_i are in general not independent; they can be seen as the result of applying the linear transformation A to a collection of independent Gaussian variables Z.

The multivariate normal can be written in the following notation:

X \sim N(\mu, \Sigma)

or to make it explicitly known X is N-dimensional

X \sim N_N(\mu, \Sigma)

Cumulative distribution function

The cumulative distribution function (cdf) F(x) is defined as the probability that all values in a random vector X are less than or equal to the corresponding values in vector x. Though there is no closed form for F(x), there are a number of algorithms that estimate it numerically. For example, see MVNDST under * (includes FORTRAN code) or * (includes MATLAB code).

A counterexample


The fact that two random variables X and Y are normally distributed does not imply that the pair (XY) has a bivariate normal distribution. A simple example is one in which Y = X if |X| > 1 and Y = −X if |X| < 1.

If X and Y are normally distributed and independent, then they are "jointly normally distributed", i.e., the pair (XY) does have a bivariate normal distribution. There are of course also many bivariate normal distributions in which the components are correlated.

Bivariate case


In the 2-dimensional nonsingular case, the probability density function (with mean (0,0)) is

f(x,y) = \frac{1}{2 \pi \sigma_x \sigma_y \sqrt{1-\rho^2}} \exp \left( -\frac{1}{2 (1-\rho^2)} \left( \frac{x^2}{\sigma_x^2} + \frac{y^2}{\sigma_y^2} - \frac{2 \rho x y}{ (\sigma_x \sigma_y)} \right) \right)

where \rho is the correlation between X and Y.

Linear transformation


If Y = B X \, is a linear transformation of X\, where B\, is an m \times p matrix then Y\, has a multivariate normal distribution with expected value B \mu \,and variance B \Sigma B^T \, (i.e., Y \sim N \left(B \mu, B \Sigma B^T\right).

Corollary: any subset of the X_i\, has a marginal distribution that is also multivariate normal. To see this consider the following example: to extract the subset (X_1, X_2, X_4)^T \,, use

B = \begin{bmatrix} 1 & 0 & 0 & 0 & 0 & \ldots & 0 \\ 0 & 1 & 0 & 0 & 0 & \ldots & 0 \\ 0 & 0 & 0 & 1 & 0 & \ldots & 0 \end{bmatrix}

which extracts the desired elements directly.

Correlations and independence


In general, random variables may be uncorrelated but highly dependent. But if a random vector has a multivariate normal distribution then any two or more of its components that are uncorrelated are independent. This implies that any two or more of its components that are pairwise independent are independent.

But it is not true that two random variables that are (separately, marginally) normally distributed and uncorrelated are independent. Two random variables that are normally distributed may fail to be jointly normally distributed, i.e., the vector whose components they are may fail to have a multivariate normal distribution. For an example of two normally distributed random variables that are uncorrelated but not independent, see normally distributed and uncorrelated does not imply independent.

Higher moments


The k-order moments of X are defined by
\mu _{1,...,N}(X)\equiv \mu _{r_{1},...,r_{N}}(X)\equiv E\left[ \prod\limits_{j=1}^{N}x^{r_{j}}\right] where r_{1}+r_{2}+...+r_{N}=k

The central k-order moments are given as follows

(a) If k is odd, \mu _{1,...,N}(X-\mu )=0.

(b) If k is even with k=2\lambda, then

\mu _{1,...,2\lambda }(X-\mu )=\sum \left( \sigma _{ij}\sigma _{kl}...\sigma _{xz}\right) where the sum is taken over all permutations of \left\{ 1,...,2\lambda \right\} giving (2\lambda -1)!/(2^{\lambda -1}(\lambda -1)!) terms in the sum each being the product of \lambda covariances

In particular, the 4-order moments are

E\leftx_{i}^{4}\right = 3\sigma _{ii}
E\leftx_{i}^{3}x_{j}\right = 3\sigma _{ii}\sigma _{ij}
E\leftx_{i}^{2}x_{j}^{2}\right = \sigma _{ii}\sigma _{jj}+2\left( \sigma _{ij}\right) ^{2}
E\leftx_{i}^{2}x_{j}x_{k}\right = \sigma _{ii}\sigma _{jk}+2\sigma _{ij}\sigma _{ik}
E\leftx_{i}x_{j}x_{k}x_{n}\right = \sigma _{ij}\sigma _{kn}+\sigma _{ik}\sigma _{jn}+\sigma _{in}\sigma _{jk}

Conditional distributions


Then if \mu and \Sigma are partitioned as follows

\mu = \begin{bmatrix} \mu_1 \\ \mu_2 \end{bmatrix} \quad with sizes \begin{bmatrix} q \times 1 \\ (N-q) \times 1 \end{bmatrix}

\Sigma = \begin{bmatrix} \Sigma_{11} & \Sigma_{12} \\ \Sigma_{21} & \Sigma_{22} \end{bmatrix} \quad with sizes \begin{bmatrix} q \times q & q \times (N-q) \\ (N-q) \times q & (N-q) \times (N-q) \end{bmatrix}

then the distribution of x_1 conditional on x_2=a is multivariate normal X_1|X_2=a \sim N(\bar{\mu}, \overline{\Sigma}) where

\bar{\mu} = \mu_1 + \Sigma_{12} \Sigma_{22}^{-1} \left( a - \mu_2 \right)

and covariance matrix

\overline{\Sigma} = \Sigma_{11} - \Sigma_{12} \Sigma_{22}^{-1} \Sigma_{21}.

This matrix is the Schur complement of {\mathbf\Sigma_{22}} in {\mathbf\Sigma}.

Note that knowing the value of x_2 to be a alters the variance; perhaps more surprisingly, the mean is shifted by \Sigma_{12} \Sigma_{22}^{-1} \left(a - \mu_2 \right); compare this with the situation of not knowing the value of a, in which case x_1 would have distribution N_q \left(\mu_1, \Sigma_{11} \right).

The matrix \Sigma_{12} \Sigma_{22}^{-1} is known as the matrix of regression coefficients.

Fisher information matrix


The Fisher information matrix (FIM) for a normal distribution takes a special formulation. The (m,n) element of the FIM for X \sim N(\mu(\theta), \Sigma(\theta)) is

\mathcal{I}_{m,n} = \frac{\partial \mu}{\partial \theta_m} \Sigma^{-1} \frac{\partial \mu^\top}{\partial \theta_n} + \frac{1}{2} \mathrm{tr} \left( \Sigma^{-1} \frac{\partial \Sigma}{\partial \theta_m} \Sigma^{-1} \frac{\partial \Sigma}{\partial \theta_n} \right)

where

\frac{\partial \mu}{\partial \theta_m} = \begin{bmatrix} \frac{\partial \mu_1}{\partial \theta_m} & \frac{\partial \mu_2}{\partial \theta_m} & \cdots & \frac{\partial \mu_N}{\partial \theta_m} & \end{bmatrix}
\frac{\partial \mu^\top}{\partial \theta_m} = \left( \frac{\partial \mu}{\partial \theta_m} \right)^\top = \begin{bmatrix} \frac{\partial \mu_1}{\partial \theta_m} \\ \\ \frac{\partial \mu_2}{\partial \theta_m} \\ \\ \vdots \\ \\ \frac{\partial \mu_N}{\partial \theta_m} \\ \\ \end{bmatrix}
\frac{\partial \Sigma}{\partial \theta_m} = \begin{bmatrix} \frac{\partial \Sigma_{1,1}}{\partial \theta_m} & \frac{\partial \Sigma_{1,2}}{\partial \theta_m} & \cdots & \frac{\partial \Sigma_{1,N}}{\partial \theta_m} \\ \\ \frac{\partial \Sigma_{2,1}}{\partial \theta_m} & \frac{\partial \Sigma_{2,2}}{\partial \theta_m} & \cdots & \frac{\partial \Sigma_{2,N}}{\partial \theta_m} \\ \\ \vdots & \vdots & \ddots & \vdots \\ \\ \frac{\partial \Sigma_{N,1}}{\partial \theta_m} & \frac{\partial \Sigma_{N,2}}{\partial \theta_m} & \cdots & \frac{\partial \Sigma_{N,N}}{\partial \theta_m} \end{bmatrix}
  • \mathrm{tr} is the trace function

Kullback-Leibler divergence


The Kullback-Leibler divergence from N0_N(\mu_0, \Sigma_0) to N1_N(\mu_1, \Sigma_1) is:

KL(N0, N1) = { 1 \over 2 } \left( \log \left( { \det \Sigma_1 \over \det \Sigma_0 } \right) + \mathrm{tr} \left( \Sigma_1^{-1} \Sigma_0 \right) + \left( \mu_1 - \mu_0\right)^\top \Sigma_1^{-1} ( \mu_1 - \mu_0 ) - N\right).

Estimation of parameters


The derivation of the maximum-likelihood estimator of the covariance matrix of a multivariate normal distribution is perhaps surprisingly subtle and elegant. See estimation of covariance matrices.

In short, the pdf is

f(x)=(2 \pi)^{-p/2} \det(\Sigma)^{-1/2} \exp\left({-1 \over 2} (x-\mu)^T \Sigma^{-1} (x-\mu)\right)

and the ML estimator of the covariance matrix is

\hat\Sigma = {1 \over n}\sum_{i=1}^n (X_i-\overline{X})(X_i-\overline{X})^T

which is simply the sample covariance matrix. This is a biased estimator whose expectation is

E* = {n-1 \over n}\Sigma.

An unbiased sample covariance is

\hat\Sigma = {1 \over n-1}\sum_{i=1}^n (X_i-\overline{X})(X_i-\overline{X})^T.

Multivariate normality tests


Multivariate normality tests check a given set of data for similarity to the multivariate normal distribution. The null hypothesis is that the data set is similar to the normal distribution, therefore a sufficiently small p-value indicates non-normal data. Multivariate normality tests include the Cox-Small test and Smith and Jain's adaptation of the Friedman-Rafsky test .

Drawing values from the distribution


A widely used method for drawing a random vector X from the n-dimensional multivariate normal distribution with mean vector \mu and covariance matrix \Sigma (required to be symmetric and positive definite) works as follows:

  1. Compute the Cholesky decomposition (matrix square root) of \Sigma, that is, find the unique lower triangular matrix A such that A\,A^T = \Sigma.
  2. Let Z=(z_1,\dots,z_n)^T be a vector whose components are n independent standard normal variates (which can be generated, for example, by using the Box-Muller transform).
  3. Let X be \mu + A\,Z.

References


Continuous distributions

loi normale multidimensionnelle | Многомерное нормальное распределение | Multivariat normalfördelning

 

This article is licensed under the GNU Free Documentation License. It uses material from the "Multivariate normal distribution".

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