In mathematics, the adjective irreducible means that an object cannot be expressed as a product of at least two non-trivial factors in a given set. See also factorization.

For any field F, the ring of polynomials with coefficients in F is denoted by

This definition depends on the field F. Some simple examples will be discussed below.

Galois theory studies the relationship between a field, its Galois group, and its irreducible polynomials in depth. Interesting and non-trivial applications can be found in the study of finite fields.

It is helpful to compare irreducible polynomials to prime numbers: prime numbers (together with the corresponding negative numbers of equal modulus) are the irreducible integers. They exhibit many of the general properties of the concept 'irreducibility' that equally apply to irreducible polynomials, such as the essentially unique factorization into prime or irreducible factors:

Every polynomial $p(x)$ in $F*$ can be factorized into polynomials that are irreducible over F. This factorization is unique up to permutation of the factors and the multiplication of constants from F to the factors.

Simple examples

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The following five polynomials demonstrate some elementary properties of reducible and irreducible polynomials:

$p\_1(x)=x^2+4x+4\backslash ,=(x+2)(x+2)$,

$p\_2(x)=x^2-4\backslash ,=(x-2)(x+2)$,

$p\_3(x)=x^2-4/9\backslash ,=(x-2/3)(x+2/3)$,

$p\_4(x)=x^2-2\backslash ,=(x-\backslash sqrt\{2\})(x+\backslash sqrt\{2\})$,

$p\_5(x)=x^2+1\backslash ,=(x-i)(x+i)$.

Over the ring Z of integers, the first two polynomials are reducible, but the other three are irreducible.

Over the field Q of rational numbers, the first three polynomials are reducible, but the other two polynomials are irreducible.

Over the field R of real numbers, the first four polynomials are reducible, but $p\_5(x)$ is still irreducible.

Over the field C of complex numbers, all five polynomials are reducible.

In fact over C, every non-constant polynomial can be factored into linear factors

$p(z)=a\_n\; (z-z\_1)(z-z\_2)\backslash cdots(z-z\_n)$

where $a\_n$ is the leading coefficient of the polynomial and $z\_1,\backslash ldots,z\_n$ are the zeros of $p(z)$. Hence, all irreducible polynomials are of degree 1. This is the Fundamental theorem of algebra.

Note: The existence of an essentially unique factorization $p\_5(x)=x^2+1=(x-i)(x+i)$ of $p\_5(x)$ into factors that do not belong to $Q*$ implies that this polynomial is irreducible over Q: there cannot be another factorization.

These examples demonstrate the relationship between the zeros of a polynomial (solutions of an algebraic equation) and the factorization of the polynomial into linear factors.

The existence of irreducible polynomials of degree greater than one (without zeros in the original field) historically motivated the extension of that original number field so that even these polynomials can be reduced into linear factors: from rational numbers to real numbers and further to complex numbers.

For algebraic purposes, the extension from rational numbers to real numbers is often too 'radical': It introduces transcendental numbers (that are not the solutions of algebraic equations with rational coefficients). These numbers are not needed for the algebraic purpose of factorizing polynomials (but they are necessary for the use of real numbers in analysis). The set of algebraic numbers is the algebraic closure of the rationals, and contains the roots of all polynomials (including i for instance). This is a countable field and is strictly contained in the complex numbers -- the difference being that this field is 'algebraically complete' (as are the complexes) but not analytically complete since it lacks the aforementioned trancendentals.

The above paragraph generalizes in that there is a purely algebraic process to extend a given field F with a given polynomial $p(x)$ to a larger field where this polynomial $p(x)$ can be reduced into linear factors. The study of such extensions is the starting point of Galois theory.

Generalization

If R is an integral domain, an element f of R which is neither zero nor a unit is called irreducible if there are no non-units g and h with f = gh. One can show that every prime element is irreducible; the converse is not true in general but holds in unique factorization domains. The polynomial ring F^* over a field F is a unique factorization domain.

Finite Fields

Factorization in a finite field can be very different from factorization over the rationals and complexes. For instance, in the finite field of two elements, GF(2), we have that the polynomial

$p\_5(x)=x^2+1\backslash ,=(x+1)^2$

is not irreducible as it was over Z or Q. This behavior occurs because finite fields have non-zero characteristic.

Generally, if a polynomial factors over Z then the corresponding polynomial with coefficients considered in the finite field GF(p) is also reducible, where p is a prime (the factors are the factors over Z reduced modulo p). The converse of this statement is not true: there are polynomials that factor modulo p for all positive primes p but that are not reducible when considered as a polynomial with integer coefficients.

See also

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• Gauss's lemma (polynomial)
• Eisenstein's criterion
• Hilbert's irreducibility theorem

Polynomials | Abstract algebra | Algebra

Irreduzibles Polynom | Polinomio irreducible | Factorisation des polynômes | פולינום אי פריק | Wielomian nierozkładalny