The Mason-Weaver equation describes the sedimentation and diffusion
of solutes under a uniform force, usually a gravitational field.
Assuming that the gravitational field is aligned in
the z direction (Fig. 1), the Mason-Weaver equation may be written
\frac{\partial c}{\partial t} =
D \frac{\partial^{2}c}{\partial z^{2}} +
sg \frac{\partial c}{\partial z}
where t is the time, c is the solute
concentration
(moles per unit length in the z-direction), and the parameters D, s,
and g represent the solute diffusion constant,
sedimentation coefficient and the (presumed constant)
acceleration of gravity, respectively.
The Mason-Weaver equation is complemented by the boundary conditions
D \frac{\partial c}{\partial z} + s g c = 0
at the top and bottom of the cell, denoted as
and
, respectively (Fig. 1).
These
boundary conditions
correspond to the physical requirement that no
solute
pass through
the top and bottom of the cell, i.e., that the
flux there be zero.
The cell is assumed to be rectangular and aligned with
the
Cartesian axes (Fig. 1), so that
the net
flux through the side walls is likewise
zero. Hence, the total amount of
solute in the cell
N_{tot} = \int_{z_{b}}^{z_{a}} dz \ c(z, t)
is conserved, i.e.,
.
The Mason-Weaver equation was first described in the paper,
"The Settling of Small Particles in a Fluid",
by Max Mason and Warren Weaver Rev., 23, 412-426 (1924).
Derivation of the Mason-Weaver equation
A typical particle of mass m moving with vertical velocity v
is acted upon by three forces (Fig. 1): the
drag force ,
the force of gravity and
the buoyant force
, where g is the acceleration of gravity,
V is the solute particle volume and is the solvent
density. At equilibrium (typically reached in roughly 10 ns
for molecular solutes), the
particle attains a terminal velocity where the
three forces are balanced. Since V equals the particle mass m
times its partial specific volume ,
the equilibrium condition may be written as
f v_{term} = m (1 - \bar{\nu} \rho) g \equiv m_{b} g
where
is the
buoyant mass.
We define the Mason-Weaver sedimentation coefficient
.
Since the drag coefficient f is
related to the diffusion constant D by
the Einstein relation
,
the ratio of s and D equals
\frac{s}{D} = \frac{m_{b}}{k_{B} T}
where
is the
Boltzmann constant and
T is the
temperature in
kelvin.
The flux J at any point is given by
J = -D \frac{\partial c}{\partial z} - v_{term} c
= -D \frac{\partial c}{\partial z} - s g c
The first term describes the
flux due to
diffusion
down a
concentration gradient, whereas the second term
describes the
convective flux due to the average velocity
of the particles. A positive net
flux
out of a small volume produces a negative change in the local
concentration within that volume
\frac{\partial c}{\partial t} = -\frac{\partial J}{\partial z}
Substituting the equation for the flux J produces
the Mason-Weaver equation
\frac{\partial c}{\partial t} =
D \frac{\partial^{2}c}{\partial z^{2}} +
sg \frac{\partial c}{\partial z}
The parameters D, s and g determine a length scale
z_{0} \equiv \frac{D}{sg}
and a time scale
t_{0} \equiv \frac{D}{s^{2}g^{2}}
Defining the dimensionless variables
and ,
the Mason-Weaver equation becomes
\frac{\partial c}{\partial \tau} =
\frac{\partial^{2} c}{\partial \zeta^{2}} +
\frac{\partial c}{\partial \zeta}
subject to the boundary conditions
\frac{\partial c}{\partial \zeta} + c = 0
at the top and bottom of the cell,
and
, respectively.
Solution of the Mason-Weaver equation
This equation may be solved by separation of variables. Defining
, we obtain the two equations coupled by a constant
\frac{\partial T}{\partial \tau} + \beta T = 0
\frac{\partial^{2} P}{\partial \zeta^{2}} +
\left
\beta - \frac{1}{4} \right P = 0
where acceptable values of are defined
by the boundary conditions
\frac{dP}{d\zeta} + \frac{1}{2} P = 0
at the upper and lower boundaries,
and
, respectively. Since the
T equation
has the solution
where
is a constant, the Mason-Weaver equation
is reduced to solving for the function
.
The ordinary differential equation for P and
its boundary conditions satisfy the criteria
for a Sturm-Liouville problem, from
which several conclusions follow. First, there is a discrete
set of orthonormal eigenfunctions
that satisfy the
ordinary differential equation
and boundary conditions. Second, the corresponding
eigenvalues are real,
bounded below by a lowest
eigenvalue
and grow asymptotically like where the
nonnegative integer k is the rank of the eigenvalue.
(In our case, the
lowest eigenvalue is zero, corresponding to the equilibrium
solution.) Third, the eigenfunctions
form a complete set;
any solution for can be
expressed as a weighted sum of the eigenfunctions
c(\zeta, \tau) =
\sum_{k=0}^{\infty} c_{k} P_{k}(\zeta) e^{-\beta_{k}\tau}
where are constant coefficients determined
from the initial distribution
c_{k} =
\int_{\zeta_{a}}^{\zeta_{b}} d\zeta \
c(\zeta, \tau=0) e^{\zeta/2} P_{k}(\zeta)
At equilibrium, (by definition)
and the equilibrium concentration distribution is
e^{-\zeta/2} P_{0}(\zeta) = B e^{-\zeta} = B e^{-m_{b}gz/k_{B}T}
which agrees with the
Boltzmann distribution.
The
function satisfies
the
ordinary differential equation and
boundary conditions
at all values of
(as may be verified by substitution), and the constant
B
may be determined from the total amount of
solute
B = N_{tot} \left( \frac{sg}{D} \right)
\left( \frac{1}{e^{-\zeta_{b}} - e^{-\zeta_{a}}} \right)
To find the non-equilibrium values of the eigenvalues
, we proceed as follows. The P equation has the form of a simple harmonic oscillator with
solutions where
\omega_{k} = \pm \sqrt{\beta_{k} - \frac{1}{4}}
Depending on the value of
,
is either purely real (
) or
purely imaginary (
). Only one
purely imaginary solution can satisfy the
boundary conditions,
namely the equilibrium solution. Hence, the non-equilibrium
eigenfunctions can be written as
P(\zeta) = A \cos{\omega_{k} \zeta} + B \sin{\omega_{k} \zeta}
where A and B are constants
and is real and strictly positive.
By introducing the oscillator amplitude and
phase as new variables,
u \equiv \rho \sin(\phi) \equiv P
v \equiv \rho \cos(\phi) \equiv - \frac{1}{\omega}
\left( \frac{dP}{d\zeta} \right)
\rho \equiv u^{2} + v^{2}
\tan(\phi) \equiv v / u
the second-order equation for
P is factored into two simple
first-order equations
\frac{d\rho}{d\zeta} = 0
\frac{d\phi}{d\zeta} = \omega
Remarkably, the transformed boundary conditions are independent
of and the endpoints and
\tan(\phi_{a}) =
\tan(\phi_{b}) = \frac{1}{2\omega_{k}}
Therefore, we obtain an equation
\phi_{a} - \phi_{b} + k\pi = k\pi =
\int_{\zeta_{b}}^{\zeta_{a}} d\zeta \ \frac{d\phi}{d\zeta} =
\omega_{k} (\zeta_{a} - \zeta_{b})
giving an exact solution for the frequencies
\omega_{k} = \frac{k\pi}{\zeta_{a} - \zeta_{b}}
The eigenfrequencies are positive as required, since , and comprise the set of harmonics of the fundamental frequency . Finally, the
eigenvalues can be derived
from
\beta_{k} = \omega_{k}^{2} + \frac{1}{4}
Taken together, the non-equilibrium components of the solution
correspond to a Fourier series decomposition of the initial
concentration distribution
multiplied by the
weighting function .
Each Fourier component decays independently as ,
where is given above in terms of the
Fourier series frequencies .
See also
External links
Laboratory techniques | Partial differential equations